x^2-36x-270=0

Solution for x^2-36x-270=0 equation:

x^2-36x-270=0

a = 1; b = -36; c = -270;
Δ = b2-4ac
Δ = -362-4·1·(-270)
Δ = 2376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2376}=\sqrt{36*66}=\sqrt{36}*\sqrt{66}=6\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{66}}{2*1}=\frac{36-6\sqrt{66}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{66}}{2*1}=\frac{36+6\sqrt{66}}{2}
$